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2-5x-x^2=0
We add all the numbers together, and all the variables
-1x^2-5x+2=0
a = -1; b = -5; c = +2;
Δ = b2-4ac
Δ = -52-4·(-1)·2
Δ = 33
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{33}}{2*-1}=\frac{5-\sqrt{33}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{33}}{2*-1}=\frac{5+\sqrt{33}}{-2} $
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